Solve 15x2 = 22x

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Solution.

Given equation is 15x² = 22x

Converting given equation into Standard Form of Quadratic Equation. ax² + bx + c = 0

15x² = 22x converted into 15x² - 22x + 0 = 0

Comparing it with the standard Form of Quadratic Equation ax² + bx + c = 0

a = 15, b = -22, c = 0

As we know, discriminant = b² - 4ac

Discriminant = (-22)² - 4(15)(0)

Discriminant = 484 - (0)

Discriminant = 484

Since discriminant > 0
Both roots are real and unequal.

Using quadratic formula

Roots(x₁, x₂) =	−b ± √ b2 − 4ac
	2a

Roots(x₁, x₂) =	−b ± √ D
	2a

x₁ =	−b + √D
	2a

=	−(-22) + √484
	2(15)

=	22 + 22
	30

=	44
	30

x₂ =	−b - √D
	2a

=	−(-22) - √484
	2(15)

=	22 - 22
	30

= 0

Roots: x₁ = , x₂ =

Sum of roots = -b/a

Sum of roots = -(-22)/(15)

Sum of roots = 1.4666666666667

Product of roots = c/a

Product of roots = (0)/(15)

Product of roots = 0

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