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Solve, x2 - 36 = 0


Solution.

Given equation is x2 - 36 = 0

Comparing it with the standard Form of Quadratic Equation ax2 + bx + c = 0

a = 1, b = 0`, c = -36

As we know, discriminant = b2 - 4ac

Discriminant = (0`)2 - 4(1)(-36)

Discriminant =

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0 - (-144)

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Discriminant =

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144

Since discriminant > 0
Both roots are real and unequal.

Using quadratic formula


Roots(x1, x2) = −b ± √   b2 − 4ac 
         2a          


Roots(x1, x2) = −b ± √ D
         2a          


x1 = −b + √D
         2a          


=   −(0`) + √144
         2(1)          


=   

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0 + 12
         2          


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= 6


x2 = −b - √D
         2a          


=   −(0`) - √144
         2(1)          


=   

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0 - 12
         2          


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= -6


Roots: x1 = -6,     x2 = 6


Sum of roots = -b/a

Sum of roots = -(0`)/(1)

Sum of roots =

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0


Product of roots = c/a

Product of roots = (-36)/(1)

Product of roots = -36
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