Solve 7x2 = 63

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Solution.

Given equation is 7x² = 63

Converting given equation into Standard Form of Quadratic Equation. ax² + bx + c = 0

7x² = 63 converted into 7x² + 0x - 63 = 0

Comparing it with the standard Form of Quadratic Equation ax² + bx + c = 0

a = 7, b = 0, c = -63

As we know, discriminant = b² - 4ac

Discriminant = (0)² - 4(7)(-63)

Discriminant = 0 - (-1764)

Discriminant = 1764

Since discriminant > 0
Both roots are real and unequal.

Using quadratic formula

Roots(x₁, x₂) =	−b ± √ b2 − 4ac
	2a

Roots(x₁, x₂) =	−b ± √ D
	2a

x₁ =	−b + √D
	2a

=	−(0) + √1764
	2(7)

=	0 + 42
	14

= 3

x₂ =	−b - √D
	2a

=	−(0) - √1764
	2(7)

=	0 - 42
	14

= -3

Roots: x₁ = 3, x₂ = -3

Sum of roots = -b/a

Sum of roots = -(0)/(7)

Sum of roots = 0

Product of roots = c/a

Product of roots = (-63)/(7)

Product of roots = -9

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