Solve -x2 + 6x + 5 = 0

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Solution.

Given equation is -x² + 6x + 5 = 0

Comparing it with the standard Form of Quadratic Equation ax² + bx + c = 0

a = -1, b = 6, c = 5

As we know, discriminant = b² - 4ac

Discriminant = (6)² - 4(-1)(5)

Discriminant = 36 - (-20)

Discriminant = 56

Since discriminant > 0
Both roots are real and unequal.

Using quadratic formula

Roots(x₁, x₂) =	−b ± √ b2 − 4ac
	2a

Roots(x₁, x₂) =	−b ± √ D
	2a

x₁ =	−b + √D
	2a

=	−(6) + √56
	2(-1)

=	-6 + √56
	-2

x₂ =	−b - √D
	2a

=	−(6) - √56
	2(-1)

=	-6 - √56
	-2

Roots: x₁ = 1, x₂ = 5

Sum of roots = -b/a

Sum of roots = -(6)/(-1)

Sum of roots = 6

Product of roots = c/a

Product of roots = (5)/(-1)

Product of roots = -5

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