Given equation is x(x - 2) = 2(x + 6)
Converting given equation into Standard Form of Quadratic Equation. ax2 + bx + c = 0
x(x - 2) = 2(x + 6) converted into x2 - 4x - 12 = 0
Comparing it with the standard Form of Quadratic Equation ax2 + bx + c = 0
As we know, discriminant = b2 - 4ac
Discriminant = (-4)2 - 4(1)(-12)
Discriminant = 16 - (-48)
Using quadratic formula
Roots(x1, x2) = | −b ± √ b2 − 4ac |
2a |
Roots(x1, x2) = | −b ± √ D |
2a |
x1 = | −b + √D |
2a |
= | −(-4) + √64 |
2(1) |
= | 4 + 8 |
2 |
= 6 |
x2 = | −b - √D |
2a |
= | −(-4) - √64 |
2(1) |
= | 4 - 8 |
2 |
= -2 |
Sum of roots = -b/a
Sum of roots = -(-4)/(1)
Product of roots = c/a
Product of roots = (-12)/(1)
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