Solve x2 + 2x + 1

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Solution.

Given equation is x² + 2x + 1 - 9 = 0

Comparing it with the standard Form of Quadratic Equation ax² + bx + c = 0

a = 1, b = 2, c = -8

As we know, discriminant = b² - 4ac

Discriminant = (2)² - 4(1)(-8)

Discriminant = 4 - (-32)

Discriminant = 36

Since discriminant > 0
Both roots are real and unequal.

Using quadratic formula

Roots(x₁, x₂) =	−b ± √ b2 − 4ac
	2a

Roots(x₁, x₂) =	−b ± √ D
	2a

x₁ =	−b + √D
	2a

=	−(2) + √36
	2(1)

=	-2 + 6
	2

= 2

x₂ =	−b - √D
	2a

=	−(2) - √36
	2(1)

=	-2 - 6
	2

= -4

Roots: x₁ = 2, x₂ = -4

Sum of roots = -b/a

Sum of roots = -(2)/(1)

Sum of roots = -2

Product of roots = c/a

Product of roots = (-8)/(1)

Product of roots = -8

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