Solve y2 + 5y

<---- Sponsored ads ------ >

Solution.

Given equation is y² + 5y - 2 = 0

Comparing it with the standard Form of Quadratic Equation ax² + bx + c = 0

a = 1, b = 5, c = -2

As we know, discriminant = b² - 4ac

Discriminant = (5)² - 4(1)(-2)

Discriminant = 25 - (-8)

Discriminant = 33

Since discriminant > 0
Both roots are real and unequal.

Using quadratic formula

Roots(x₁, x₂) =	−b ± √ b2 − 4ac
	2a

Roots(x₁, x₂) =	−b ± √ D
	2a

x₁ =	−b + √D
	2a

=	−(5) + √33
	2(1)

=	-5 + √33
	2

x₂ =	−b - √D
	2a

=	−(5) - √33
	2(1)

=	-5 - √33
	2

Roots: x₁ = , x₂ =

Sum of roots = -b/a

Sum of roots = -(5)/(1)

Sum of roots = -5

Product of roots = c/a

Product of roots = (-2)/(1)

Product of roots = -2

<---- Sponsored ads ----- >