The quadratic equation solver is an online calculator to solve a standard quadratic equation.
As the name suggests, Quadratic equation solver solves any quadratic equation, which is in the form of ax2 + bx + c = 0, where a ≠ 0, using a Quadratic Formula.
By solving the quadratic equation, Quadratic Equation Solver arrives at values of x, for which the quadratic equation ax2 + bx + c = 0 holds true. This means, that when we replace x in ax2 + bx + c with the values calculated from quadratic equation solver, then ax2 + bx + c calculates to zero.
The simple formula to calculate the values of x for which ax2 + bx + c = 0 holds true, is called Quadratic Formula:
Roots(x1, x2) = | −b ± √ b2 − 4ac |
2a |
As you can notice in the formula. This implies, Quadratic formula calculates two values of x: x1 and x2, where
x1 = | −b + √ b2 − 4ac |
2a |
x2 = | −b - √ b2 − 4ac |
2a |
These two values of x for which ax2 + bx + c = 0 holds true, are called solutions of Quadratic Equation, also called roots of Quadratic Equation.
◾ If b2 – 4ac > 0, then √b2 − 4ac is real; hence we get two real and distinct roots.
◾ If b2 – 4ac = 0, then √b2 − 4ac is also zero; hence values of both x1 and x2 would be same and hence we get real and equal roots.
◾ If b2 – 4ac < 0, then √b2 − 4ac is imaginary number; hence we get imaginary roots.
◾ If b2 – 4ac is a perfect square, then √b2 − 4ac is a rational number; hence we get rational roots, else we get irrational roots.
Step 1 - Convert the Quadratic Equation you wish to solve in Standard Form of Quadratic Equation, ax2 + bx + c = 0
For example, if you have a quadratic equation in the form of x2 - 6x = -8, then convert it into Standard Form of Quadratic Equation.
x2 -6x = -8 is converted into x2 - 6x + 8 = 0
Step 2 - Find value of coefficient a, b and c by comparing it with Standard Form of Quadratic Equation ax2 + bx + c = 0
For example, comparing x2 - 6x - 8 = 0 with ax2 + bx + c = 0, we get
a = 1,
b = -6,
c = 8
Step 3
Roots(x1, x2) = | −b ± √ b2 − 4ac |
2a |
x1 = | −b + √ b2 − 4ac |
2a |
= | −(-6) + √ (-6)2 − 4(1)(8) | = 4 |
2(1) |
x2 = | −b - √ b2 − 4ac |
2a |
= | −(-6) - √ (-6)2 − 4(1)(8) | = 2 |
2(1) |
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